Physics - NLM Question with Solution | TestHub

PhysicsNLMChallenging application of NLMMedium2 minQB

PhysicsMediumsingle choice

In figure $m_{1} = 4 kg, m_{2} = 2 kg$ and $F = 10 N$ . The breaking strength of the string connected to masses is 25 N. The system is set to motion.

Answer:

Solution:

Take $g = 10 m/ s^{2}$ . If the string holds: $F + m_{1} g - T = m_{1} a$ and $T - m_{2} g = m_{2} a$ .

Adding: $10 + 40 - 20 = 6 a \Rightarrow a = 5 m/ s^{2}$ . Then $T = m_{2} (g + a) = 2 (15) = 30 N$ .

$T = 30 N > 25 N$ , so the string breaks.

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Challenging application of NLM

⏱ 2mℹ️ Source: QB

Loading discussions...