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Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionEasy2 minQB

PhysicsEasynumerical

Coefficient of kinetic friction between $3 kg$ and $2 kg$ block is $0.25$ . The horizontal table surface is smooth. Find the acceleration (in S.I unit) of the block of mass $10 kg$ .

Answer:

6.00

Solution:

$100 - T_{2} = 10 a$

$T_{2} - T_{1} - 0.25 \times 20 = 3 a$

$T_{1} - 0.25 \times 20 = 2 a$

Adding the above three equations and solving for acceleration we get

$a = \frac{100 - 0.25 \times 20 - 0.25 \times 20}{15} = 6 m s^{- 2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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