A block starts moving up a fixed inclined plane of inclination 60 ∘ with a velocity of 20 ms - 1 and stops after 2 s . The approximate value of the coefficient of friction is [ g = 10 ms - 2 ]

Retardation of the block is a = g sin θ + μ cos θ = 5 3 + μ v = u - a t = 0 ⇒ a = u t ⇒ 5 3 + μ = 20 2 ⇒ μ = 0 . 27

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A block starts moving up a fixed inclined plane of inclination $60^{\circ}$ with a velocity of $20 {ms}^{- 1}$ and stops after $2 s$ . The approximate value of the coefficient of friction is [ $g = 10 {ms}^{- 2}$ ]

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Solution:

Retardation of the block is

$a = g (sin θ + μ cos θ) = 5 (\sqrt{3} + μ)$

$v = u - a t = 0 \Rightarrow a = \frac{u}{t} \Rightarrow 5 (\sqrt{3} + μ) = \frac{20}{2} \Rightarrow μ = 0.27$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

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