Spring constant of weighing machine reduces due to severe use of it. If a man on weighing machine gets correct reading if elevator goes with $2 m / s^{2}$ if \% change in spring constant is P, then fill (P - 16) if lift goes upward or (P - 17) if lift goes downward.

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x would be the same. m g m g ′ ​ = k x = k ′ x ​ As k 1 ​ < k ⇒ g ′ < g , so g ′ = g 0 ​ − 2 , and the lift goes downward.

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