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Physics - NLM Question with Solution | TestHub

PhysicsNLMChallenging application of NLMEasy2 minQB

PhysicsEasynumerical

A ring of mass $5 kg$ sliding on a frictionless vertical rod connected by a block $B$ of mass $10 kg$ by the help of a massless string. Then at equilibrium, the value of $θ$ (in degree) is

Answer:

60.00

Solution:

For ring,

From force diagram of ring,

$T \cos θ = m_{1} g$ ......(i)

For block B.

$m g = T$ ........ (ii)

$T \cos θ = m_{1} g$

$m g \cos θ = m_{1} g$

$∴$ $\cos θ = \frac{m_{1}}{m} = \frac{5}{10} = \frac{1}{2}$

$\Rightarrow$ $θ = 60^{o}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Challenging application of NLM

⏱ 2mℹ️ Source: QB

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