Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionEasy2 minQB
PhysicsEasysingle choice

A conveyor belt is moving at a constant speed of2 m s−1.  A box is gently dropped on it. The coefficient of friction between them is μ=0.5. The distance that the box will move relative to belt before coming to rest on it takingg=10m s−2, is

Options:

Answer:
D
Solution:

The frictional force on the box   f=μmg

  ∴   Acceleration in the box

                 a=μg=5 m  s −2

v2=u2+2as

4=0+2×5×s

s = 0.4 m

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...