The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I, the mass m is lifted by attaching a mass 2 m to the other end of the rope. In case II, the mass

Question

The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I, the mass m is lifted by attaching a mass 2 m to the other end of the rope. In case II, the mass m is lifted by pulling the other end of the rope with a constant downward force $F = 2 mg$ , where g is acceleration due to gravity. The acceleration of mass m in case I is:

TestHub · Accepted Answer

(ii) T − mg = ma I ​ 2 mg − T = 2 ma I ​ (i) + (ii) mg = 3 ma l ​ a I ​ = 3 g ​ T − mg = ma II ​ 2 mg − mg = ma II ​ a II ​ = g So a II ​ > a I ​

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