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PhysicsNLMFBD & EquilibriumMedium2 min

PhysicsMediummultiple choice

In the figure shown string CA and DF are horizontal and $T_{1}, T_{2}, T_{3}$ and $T_{4}$ are tension in the string $CA, DF$ , AD and AB. then

Answer:

B, C

Solution:

String AD makes 37° with the horizontal; the 3 kg block (30 N) hangs from D.

At D: $T_{3} sin 3 7^{\circ} = 30 N \Rightarrow T_{3} = 50 N$ ; $T_{2} = T_{3} cos 3 7^{\circ} = 40 N$ .

At A: $T_{1} = T_{3} cos 3 7^{\circ} = 40 N$ , $T_{4} = T_{3} sin 3 7^{\circ} = 30 N$ . So T1 = T2 = 40 N and T3 = 50 N.

Answer: (B), (C)

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

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