A man of mass 60 kg stands on a frame of mass 30 kg. He pulls on a light rope which passes over a pulley, the other end of the rope being attached to the frame, as shown in the figure. The force the m

Question

A man of mass 60 kg stands on a frame of mass 30 kg. He pulls on a light rope which passes over a pulley, the other end of the rope being attached to the frame, as shown in the figure. The force the man must exert on the rope for the system to be in equilibrium is: (Take $g = 10$ m/s²)

Options:

Answer:

A

Solution:

$T = \frac{( 30 + 60 ) \times 10}{2} = 450 N .$

Option A.

TestHub · Accepted Answer

T = 2 ( 30 + 60 ) × 10 ​ = 450 N . Option A.

Physics - NLM Question with Solution | TestHub

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