A 20 kg slab rests on a frictionless floor with a 5 kg block on top; μ s = 0.5 and μ k = 0.3 between block and slab. A horizontal force of 40 N acts on the block. The acceleration of the slab is:

Question

A 20 kg slab rests on a frictionless floor with a 5 kg block on top; μ s ​ = 0.5 and μ k ​ = 0.3 between block and slab. A horizontal force of 40 N acts on the block. The acceleration of the slab is: (Take g = 10 m/s²)

TestHub · Accepted Answer

Static limit = 25 N; together would need a = 1.6 m/ s 2 and friction 32 N > 25 N, so slipping occurs; slab acceleration = 20 0.3 × 50 ​ = 0.75 m/ s 2 . Option A.

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