Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionEasy2 minQB
PhysicsEasysingle choice

A particle is projected directly along a rough plane of inclinationθwith velocityu. If after coming to the rest the particle returns to the starting point with velocityv, the coefficient of friction between the particle and the plane is

Options:

Answer:
B
Solution:

u2 = 2as

For upward motionu2=2(μgcosθ+gsinθ)s

For downward motionv2=2(gsinθ-μgcosθ)s

u2v2=μcosθ+sinθsinθ–μcosθ

u2sinθ-u2μcosθ=μv2cosθ+v2sinθ

(u2-v2)sinθ=μ(v2+u2)cosθ

μ=u2–v2u2+v2tanθ

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction
⏱ 2mℹ️ Source: QB

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