Physics - NLM Question with Solution | TestHub

Let $m_1$ move with speed $v$. (a): the string is fixed in length, so $m_2$ moves at $v_1=v$.

(b): $m_2$ hangs from a movable pulley, so it moves at half the string speed: $v_2=\frac{v}{2}$.

(c): the movable pulley carries the string whose free end moves at $v$; here the pulley moves at twice the speed: $v_3=2v$.

$v_1:v_2:v_3=1:0.5:2=2:1:4$.