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PhysicsNLMFrictionMedium2 minQB

PhysicsMediuminteger

The acceleration of block (in $m / s^{2}$ ) will be (block was initially at rest) :-

Block on rough horizontal ground with 2 N rightward force and friction coefficient 0.4

Answer:

Solution:

Maximum static friction:
$f_{s}^{m a x} = μ_{s} N = 0.4 (4) (10) = 16 N$
Applied force is only 2 N, so the block remains at rest.
$a = 0 m/ s^{2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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