Physics - NLM Question with Solution | TestHub

Now, the length of the incline is $1.5m$, and the acceleration of the block along the incline is $a=(g-6)\sin 30^{\circ }$.

Thus, $a=1.9m/s^2$. The initial velocity of the block is zero. Applying the second equation of motion along the inclined plane in the frame of the elevator, we have:

$$s=ut+\frac{1}{2}a{t}^2$$

$$1.5=0\times t+\frac{1}{2}\times 1.9\times t^2$$

$$t^2=\frac{2\times 1.5}{1.9}$$

$$t=1.26s$$

Hence, the time taken by the object to arrive at the bottom is $1.26$ seconds.