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PhysicsNLMFrictionEasy2 minQB
PhysicsEasysingle choice

A block of mass200 kgis being pulled by some men, up an inclined plane of inclination45°and coefficient of friction0.5, as shown in the figure. If each man can apply a maximum force of500 N, then the minimum number of men required to just slide the block, up the plane is


Options:

Answer:
C
Solution:

Total force required




F=mgsin⁡θ+f

=mgsin⁡θ+μsR

=mgsin⁡θ+μs mgcos⁡θ

=mg(sin⁡θ+μscos⁡θ)

=200×9.8(sin⁡45°+0.5cos⁡45°)

F=200×9.8×322

The number of men required will be

200×9.8×3(500)×22=4.1

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction
⏱ 2mℹ️ Source: QB

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