Physics - NLM Question with Solution | TestHub

The wire is nearly horizontal but sags slightly. Vertical balance at the performer: $2T\sin \varphi =W$, where $\varphi$ is the small angle of the wire with the horizontal.

Since $\varphi$ is very small, $T=\frac{W}{2\sin \varphi }\gg W$: the tension is much more than $W$.