A block of mass 1 kg is placed over a long plank of mass 3 kg . The friction coefficient between block and plank is 0.5 . The system is placed over a smooth horizontal surface. A time varying force $F = 5 t$ Newton starts acting on the block as shown in figure. Select the CORRECT alternative:-

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The block will lose contact at t = 10/3 sec . 4 t = 4 a ⟹ a = t m / s 2 0.5 N = 2 1 ​ ( 10 − 3 t ) = 3 t 10 − 3 t = 6 t t = 9 10 ​ sec Relative slipping starts at t = 10/9 sec .

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Options:(select one or more)

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