Start Free Mock LoginAlready registered? Login here

Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

A block B of mass m is kept over a wedge A of mass M as shown in the figure. Wedge is kept over a frictionless horizontal surface.

If coefficient of friction between wedge & block is $μ$ , the maximum acceleration of the wedge so that block does not slip over wedge is $(tan θ > μ)$

Options:

Answer:

Solution:

ma $cos θ = f_{r} + mg sin θ$

$ma cos θ = μ (m g cos θ + ma sin θ) + m g sin θ$

$ma [cos θ - μ sin θ] = mg (sin θ + μ cos θ)$

$a = \frac{( t a n θ + μ )}{( 1 - μ t a n θ )}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...