On both sides of pulley we hang two blocks with the same mass M. At the same time we put two masses on the blocks: on the right - a mass of 3m and on the left-m . Determine the Normal force N (in N) a

Question

On both sides of pulley we hang two blocks with the same mass M. At the same time we put two masses on the blocks: on the right - a mass of 3m and on the left-m . Determine the Normal force N (in N) acting on the mass 3 m . Take $m = 2 kg, M = 1 kg$ . Fill $\frac{N}{4}$ in OMR sheet.

$m = 2 kg, M = 1 kg, OMR \frac{N}{4}$

TestHub · Accepted Answer

Left side: M + m ; right side: M + 3 m . Acceleration: a = 4 m + 2 M ( 3 m + M ) − ( m + M ) ​ g = ( 2 m + M ) m g ​ With m = 2 , M = 1 : a = 5 20 ​ = 4 m/s 2 For the 3m mass: 3 m g − N = 3 ma N = 3 m ( g − a ) = 6 × 6 = 36 N 4 N ​ = 9

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