A cubical block is floating in a liquid with one third of it's volume immersed in the liquid. When the whole system accelerates upwards with acceleration of g /2 .

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If the volume immersed initially is ( V /3 ) . Then 3 V ​ ρ g = m g (i) If the volume immersed when the system accelerates is V then V ′ ρ ( g + 2 g ​ ) − m g = 2 m g ​ ⇒ V ′ = 3 V ​

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JEE Advanced (2028)