Physics - NLM Question with Solution | TestHub
For the system shown in figure, . Initially, the system is at rest in equilibrium condition. if the string joining and ground is cut, then just after the string is cut : (i) remain stationary. (ii) The value of acceleation of all the 4 blocks can be determined. (iii) Only remains stationary. (iv) Only accelerates. (v) All the four blocks remain stationary. Now, choose the correct option.
Options:
Answer:
Solution:
Before the cut the spring forces and string tensions are fixed by the weights. Spring forces cannot change instantly when the string joining to the ground is cut.
Blocks (left side) and (right side) still have the same forces on them as before, so they remain at rest. Only has lost the downward pull of the ground string, so it accelerates upward (the spring pull exceeds its weight). Statements (i), (ii) and (iv) are correct (all four accelerations are determinable: 0, 0, 0 and a nonzero value for ); (iii) and (v) are false.
