A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 6 0 ∘ with it. The other end rests on a rough horizontal floor. The friction force that the floor exe

Question

A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 6 0 ∘ with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (take g = 10 m / s 2 )NEET 2025

TestHub · Accepted Answer

N 2 ​ = mg = 200 N Taking torque about A : ​ f s ​ L cos 6 0 ∘ + mg 2 L ​ sin 6 0 ∘ = N 2 ​ L sin 6 0 ∘ f s ​ ( 2 1 ​ ) + 200 ( 2 1 ​ ) 2 3 ​ ​ = 200 2 3 ​ ​ f s ​ = 100 3 ​ N ​

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