Physics - NLM Question with Solution | TestHub

Given, mass of a bullet, $m=35\text{ g}=35\times 10^{-3}\text{ kg}$

Speed of the bullet, $v=600\text{ m/s}$

Maximum force exerted by the person, $F=147\text{ N}$

Let $n$ be the number of bullets fired per second.

The force exerted by the gun is equal to the rate of change of momentum of the bullets.

$F=n\times m\times v$

$147=n\times (35\times 10^{-3})\times 600$

$147=n\times 21$

$n=\frac{147}{21}=7$

The number of bullets that can be fired per second is $7$.

Answer: 7