Physics - NLM Question with Solution | TestHub

Let the masses of the blocks be $m_1=6\text{ kg}$ and $m_2=4\text{ kg}$.

The total mass of the system is $M=m_1+m_2=6+4=10\text{ kg}$.

Since the surface is smooth, the common acceleration of the system is given by:

$a=\frac{F}{M}=\frac{5}{10}=0.5{\text{ m/s}}^2$

The force on the lighter block is the contact force exerted by the heavier block. Let this force be $N$.

Applying Newton's second law to the lighter block ($m_2$):

$N=m_2\times a$

$N=4\times 0.5=2\text{ N}$

Answer: 2 N