A block of mass 200 g is kept stationary on a smooth inclined plane by applying a minimum horizontal force F = x N as shown in figure. The value of x = _ _ _ _ _ .

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Balancing the forces in horizontal direction $N \sin θ = F$

And balancing the forces in vertical direction $N \cos θ = m g$

$\Rightarrow \tan θ = \frac{F}{m g}$ $\Rightarrow F = m g \tan θ$

$F = 0.2 \times 10 \times \sqrt{3} = \sqrt{12} N$ . Therefore, $x = 12$

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