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PhysicsNLMFrictionMedium2 minPYQ_2021

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A block of mass $m$ slides along a floor while a force of magnitude $F$ is applied to it at an angle $θ$ as shown in figure. The coefficient of kinetic friction is $μ_{K}$ . Then, the block's acceleration $a$ is given by : ( $g$ is acceleration due to gravity)

Options:

Answer:

Solution:

$N = m g - f \sin θ$

$F \cos θ - μ_{k} N = m a$

$F \cos θ - μ_{k} (m g - F \sin θ) = m a$

$a = \frac{F}{m} \cos θ - μ_{K} (g - \frac{F}{m} \sin θ)$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: PYQ_2021

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