A steel block of 10 kg rests on a horizontal floor as shown. When three iron cylinders are placed on it as shown, the block and cylinders go down with an acceleration 0 . 2 m s - 2 . The normal reacti

Question

A steel block of 10 kg rests on a horizontal floor as shown. When three iron cylinders are placed on it as shown, the block and cylinders go down with an acceleration 0 . 2 m s - 2 . The normal reaction R ' by the floor if mass of the iron cylinders are equal and of 20 kg each is in N , [Take g = 10 m s - 2 and μ s = 0 . 2

TestHub · Accepted Answer

Writing force equation in vertical direction,
$M g - N = M a$
$\Rightarrow 70 g - N = 70 \times 0.2$
$\Rightarrow N = 70 [g - 0.2] = 70 \times 9.8$
$∴ N = 686$ newton
Note: Since there is no compressive normal from the sides, hence friction will not act.
Hence option $2 .$

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