Physics - NLM Question with Solution | TestHub

For$A,$$m_{A}a=f_{L_1}$

$m_{A}a={\mu }_1{m}_{A}g$

$a={\mu }_{1}g$

For$B,$

$F-\left(f_{L_1}+f_{L_2}\right)=m_{B}a$

$F={\mu }_1\left(m_{A}g\right)+{\mu }_2\left(m_A+m_B\right)g+m_B\left({\mu }_{1}g\right)$

$F=\left({\mu }_1+{\mu }_2\right)\left(m_A+m_B\right)g$

$F=\left(0.2+0.4\right)\left(2+4\right)10$

$F=36 \mathrm{N}$