A man weighing 80 k g is standing in a trolley weighing 320 kg . The trolley is resting on frictionless horizontal rails. If the man starts walking on the trolley with a speed of 1 m s - 1 , then afte

Question

A man weighing 80 k g is standing in a trolley weighing 320 kg . The trolley is resting on frictionless horizontal rails. If the man starts walking on the trolley with a speed of 1 m s - 1 , then after 4 s his displacement relative to the ground will be

TestHub · Accepted Answer

If the man starts walking on the trolley in the forward direction then whole system will move in backward direction with same momentum.

The momentum of man in forward direction = Momentum of the system $(m a n + t r o l l e y)$ in the backward direction

$\Rightarrow$ $80 \times 1 = (80 + 320) \times v \Rightarrow v = 0.2 m s^{- 1}$

So the velocity of the man with respect to ground $1 .0 - 0 .2 = 0 .8 m s^{- 1}$

$∴$ Displacement of the man with respect to $ground = 0 .8 \times 4 = 3 .2 m$

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