In the figure shown the velocity of lift is $2 m s^{- 1}$ upwards while the string is winding on the motor shaft with velocity $2 m s^{- 1}$ and block $A$ is moving downwards with a velocity of $2 m s^{- 1}$ , then find out the velocity of block $B$ .

Question

TestHub · Accepted Answer

Let, v B = velocity of block B v A L = velocity of block A with respect to lift v L = velocity of lift v B = − v A L + v L + v winding = − ( v A − v L ) + v L + v winding = − ( − 2 − 2 ) + 2 + 2 = 8 m s - 1

Physics - NLM Question with Solution | TestHub

Options:

Doubts & Discussion