Physics - NLM Question with Solution | TestHub

The total power divided by the external agent is mainly consumed in two parts:

(1) To move the body in the forward direction.
(2) To compensate the effect of the friction.
(i) Work done in moving the body
W₁= F . S
W₁= ma S …(1)
(ii) Work done agent friction
W₂= f_k× S =${\mu }_k$R S =${\mu }_k$W S
W₂=${\mu }_k$mg S …(2)
Net work done W = W₁+ W₂
W = ma S +${\mu }_k$mg S
W = m (a +$\mu$g) S
Now, according to 2^ndequation of motion
S = u +$\frac{1}{2}$at²
Now the power divided:–
$P=\frac{dw}{dt}=\frac{d}{dt}m\left(a+\mu g\right)\frac{1}{2}a{t}^2$
P = m(a +$\mu$g) at