Physics - NLM Question with Solution | TestHub

maximum friction force

$f_{\max }=\mu N$

$=\mu mg\cos 30°$

$=0.8\times 1\times 10\times \frac{\sqrt{3}}{2}$

$=4\sqrt{3}$

$=6.92\mathrm{ N}$

And$mg\sin 30°=1\times 10\times \frac{1}{2}\text{ = }5\mathrm{ N}$

Also$T+f=mg\sin 30°$

Since, the frictional force is more as compare to force$\left(mg\mathrm{s}\mathrm{i}\mathrm{n}30°\right)$i.e.,$6.92\mathrm{ N}>5\mathrm{ N}.$

Therefore, the tension in the string would be zero. No motion will take place.