Physics - NLM Question with Solution | TestHub

Forces acting on the mass are shown in figure.



For vertical direction no motion occurs

$\therefore R+F\text{sin }\theta =\mathit{\text{mg}}$

Along horizontal

$F\text{cos}\theta -f=\text{ma}$, where a is acceleration

or$F\text{cos}\theta -\mu \mathit{\text{R}}=\mathit{\text{ma}}$

$F\text{cos}\theta -\mu \left(\mathit{\text{mg}}-F\text{sin}\theta \right)=\mathit{\text{ma}}$

$a=\frac{F}{m}\left(\text{cos}\theta +\mu \text{sin}\theta \right)-\mu \text{g}$