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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two masses $m_{1}$ and $m_{2} (m_{1} > m_{2})$ are connected by a massless flexible and inextensible string passed over a massless and frictionless pulley. The acceleration of the centre of mass is

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Answer:

Solution:

Acceleration of each $m a s s = a = (\frac{m_{1} - m_{2}}{m_{1} + m_{2}}) g$

Now acceleration of centre of mass of the system

$A_{c m} = \frac{m_{1} \vec{a_{1}} + m_{1} \vec{a_{2}}}{m_{1} + m_{2}}$

As both masses move with same acceleration but in opposite direction so $\vec{a_{1}} = - \vec{a_{2}} = a$ (let)

m1-m2m1+m2×m1-m2m1+m2×g

$= {(\frac{m_{1} - m_{2}}{m_{1} + m_{2}})}^{2} \times g$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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