Physics - NLM Question with Solution | TestHub

Given, $\mathrm{a}=5 \mathrm{m} {\mathrm{s}}^{-2}, \mathrm{m}=1\mathrm{kg}, \mathrm{\mu }=\text{0.6}$.

$\therefore$  Maximum static frictional force ${\mathrm{f}}_{\mathrm{s}}={\mathrm{\mu }}_{\mathrm{s}}\mathrm{mg}=0.6\times 1\times 10=6 \mathrm{N}$
Force on a block due to acceleration of truck${\mathrm{F}}_{\mathrm{ext}}=\mathrm{ma}=1\times 5=5 \mathrm{N}$
Hence,${\mathrm{F}}_{\mathrm{ext}}<{\mathrm{f}}_{\mathrm{s}}$
Therefore, force of friction = external force =$5 \mathrm{N}$