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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A boy of mass $50 kg$ is climbing a vertical pole at a constant speed. If coefficient of friction between his palms and the pole is $0.75$ , then the normal reaction between him and the pole is (take $g = 10 m / s^{2}$ )

Options:

Answer:

Solution:

Let the normal reaction is $N .$

Since, the boy is climbing with constant speed.

$∴ F_{n e t} = 0$ (on the boy)

Free body diagram

$m g = f_{r}$ (friction force)

$m g = μ N$ $(∵ f_{r} = μ N)$

$\Rightarrow N = \frac{m g}{μ} = \frac{50 \times 10}{0.75}$

$= 666.67 N$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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