A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to the mass of 3 m moving vertically upward (along the y-axis) with velocity 2 v . The final velocity of the combina

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A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to the mass of 3 m moving vertically upward (along the y-axis) with velocity 2 v . The final velocity of the combination is

TestHub · Accepted Answer

As the two masses stick together after collision, hence it is inelastic collision. Therefore, only momentum is conserved.

$∴ m v \hat{i} + 3 m (2 v) \hat{j} = (4 m) \vec{v}$

$\vec{v} = \frac{v}{4} \hat{i} + \frac{6}{4} v \hat{j} = \frac{v}{4} \hat{i} + \frac{3}{2} v \hat{j}$

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