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PhysicsNLMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A 0.2 kg object at rest is subjected to a force 0.3 i⁡ ^ - 0.4 j⁡ ^ newton. The velocity vector after 6s is

Options:

Answer:
A
Solution:

Here, m = 0.2 kg ; u = 0

F → = 0.3 i ^ - 0.4 j ^ N

v → = ? ,  t = 6 s

a → = F → m = 0.3 i ^ - 0.4 j ^ 0.2 = 3 2 i ^ - 2 j ^

From v → = u → + a → t ,  v → = 0 + 3 2 i ^ - 2 j ^ × 6

= 9 i ^ - 1 2 j ^

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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