Physics - NLM Question with Solution | TestHub

Case A

For mass$m$

$T-mg=ma$                                (i)

For mass $2m$

$2mg-T=2ma$  (ii)



From (i) and(ii), we get –

$a=\frac{g}{3}$                                                                         …(iii)

Case B

$T – mg = ma\text{'}$

$\Rightarrow 2mg-mg=ma\text{'}$               $\left[\because T=2mg\right]$

$\therefore a\text{'}=g$                                                                    …(iv)