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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Three blocks of masses $m_{1}, m_{2}$ and $m_{3}$ are placed on a horizontal frictionless surface. A force of $40 N$ pulls the system then calculate the value of $T$ , if $m_{1} = 10 kg, m_{2} = 6 kg, m_{3} = 4 k g$ .

Options:

Answer:

Solution:

$a = \frac{F}{m_{1} + m_{2} + m_{3}}$

$a = \frac{40}{10 + 6 + 4}$

$a = 2 m s^{- 2}$

taking blocks of masses $m_{2}$ and $m_{3}$ as a system,

$40 - T = 10 \times 2$

$T = 20 N$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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