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Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionHard2 minPYQ_2020

PhysicsHardsingle choice

A child starts running from rest along a circular track of radius ' $r^{'}$ ' with constant tangential acceleration 'a'. After time 't' he feels that slipping of shoes on the ground has started. The coefficient of friction between shoes and the ground is $[g =$ acceleration due to gravity $]$

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Answer:

Solution:

(D) After time t, velocity $V =$ at $∴$ radial acceleration $a_{r} = \frac{V ^{2}}{r} = \frac{a ^{2} t ^{2}}{r}$ Total acceleration $= \frac{a ^{4} t ^{4}}{r ^{2}} + a^{2}$ $∴ μg = \frac{a ^{4} t ^{4} + a ^{2} r ^{2}}{r ^{2}}$ $∴ μ = \frac{[ a ^{4} t ^{4} + a ^{2} r ^{2} ] ^{\frac{1}{2}}}{g r}$

Stream:MHT_CETSubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: PYQ_2020

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