Two blocks each of mass m are joined together using an ideal spring of force constant K and natural length l 0 . The blocks are touching each other when the system is released from rest on a rough hor

Question

Two blocks each of mass m are joined together using an ideal spring of force constant $K$ and natural length $l_{0}$ . The blocks are touching each other when the system is released from rest on a rough horizontal surface. Both the blocks come to rest simultaneously when the extension in the spring is $\frac{l_{0}}{4}$ . The coefficient of friction between each block and the surface (assuming it to be same between any of the blocks and the surface) is:

Options:

Answer:

C

Solution:

Work energy theorem,

$- μ m g (l_{0} + \frac{l_{0}}{4}) = \frac{1}{2} K {(\frac{l_{0}}{4})}^{2} - \frac{1}{2} K l_{0}^{2}$

$μ = \frac{3 K l_{0}}{8 m g}$

TestHub · Accepted Answer

Work energy theorem, - μ m g l 0 + l 0 4 = 1 2 K l 0 4 2 - 1 2 K l 0 2 μ = 3 K l 0 8 m g

Physics - NLM Question with Solution | TestHub

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