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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two blocks of masses $M = 3 kg$ and $m = 2 kg$ , are in contact on a horizontal table. A constant horizontal force $F = 5 N$ is applied to block $M$ as shown. There is a constant frictional force of $2 N$ between the table and the block $m$ but no frictional force between the table and the first block $M$ , then the acceleration of the two blocks is

Options:

Answer:

Solution:

Net force $=$ total mass $\times$ accelaration

$a = \frac{F - f}{M + m}$

$a = \frac{5 - 2}{3 + 2}$

$a = 0.6 {m s}^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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