Start Free Mock LoginAlready registered? Login here

Physics - NLM Question with Solution | TestHub

PhysicsNLMFBD & EquilibriumEasy2 minPYQ_2020

PhysicsEasysingle choice

A man of mass $60 kg$ climbed down using an elevator. The elevator had an acceleration of $4 m s^{- 2}$ .If the acceleration due to gravity is $10 m s^{- 2}$ ,the man's apparent weight on his way down is

Options:

Answer:

Solution:

The man is climbing down using the elevator, so the resultant gravity on the man will be

$∵ g^{'} = g - a = 10 - 4$

$= 6 m s^{- 2}$

The weight of the person, $W = m g^{'}$

$= 60 \times 6 = 360 N$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...