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PhysicsNLMFrictionMedium2 minPYQ_2019
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Two blocks Aand Bof massesmA=1 kgandmB=3 kgare kept on the table as shown in figure. The coefficients of friction betweenAandBis0.2and between Band the surface of the table is also0.2.The maximum forceFthat can be applied onBhorizontally, so that the block Adoes not slide over the blockBis : [Take g=10 m/s2]

Question diagram: Two blocks A and B of masses m A = 1 k g and m B = 3 k g are

Options:

Answer:
A
Solution:

Maximum possible acceleration of1 kgblocka=µmgm=µg=2 m/s2

For1 gblock not to slide the maximum acceleration of both blocks should be

Fmax-µmg=mamax
Fmax-0.2×4×10=4×2
Fmax- 8=8
Fmax=16 N

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction
2mℹ️ Source: PYQ_2019

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