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PhysicsNLMFBD & EquilibriumEasy2 minPYQ_2019

PhysicsEasysingle choice

A mass of $10 kg$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of $45 °$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is $(g = 10 m s^{- 2})$

Options:

Answer:

Solution:

$T \cos 45 ° = m g$

$T \sin 45 ° = F$

$t a n 45 ° = \frac{F}{m g}$

$F = m g = 100 N$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2019

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