Physics - NLM Question with Solution | TestHub

According to the question, we can draw the following diagramHere, $T$ is the tension in the string. In equilibrium condition. For mass $m_1,T-m_{1}g=m_{1}a$....(i) For mass $m_2,m_{2}g-T=m_{2}a$....(ii) After adding Eqs. (i) and (ii), we get $$\begin{array}{rl}{m}_{2}g-m_{1}g& =m_{1}a+m_{2}a\\ \left(m_2-m_1\right)g& =\left(m_1+m_2\right)a\\ a& =\frac{\left(m_2-m_1\right)}{\left(m_1+m_2\right)}g\end{array}$$