A block of mass m is placed on a smooth inclined wedge $A B C$ of inclination $θ$ as shown in the figure. The wedge is given an acceleration $a$ towards the right. The relation between $a$ and $θ$ for the block to remain stationary on the wedge is

NEET 2018

Question

TestHub · Accepted Answer

In non-inertial frame of wedge

Using pseudo force,
Free body diagram is given as

Normal reaction is balanced by $m g \cos (θ)$
Where m is mass of the body,
g is the acceleration due to gravity
a is the acceleration produced by external force..
$m a \cos θ = m g \sin θ$
$a = \frac{g \sin (θ)}{\cos (θ)}$

$a = g \tan θ$

Physics - NLM Question with Solution | TestHub

Options:

Doubts & Discussion