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Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionEasy2 minPYQ_2016

PhysicsEasysingle choice

A marble block of mass $2 kg$ lying on ice when given a velocity of $6 m / s$ is stopped by friction in $10 s$ . Then the coefficient of friction is (Take $g =$ $10 ms^{- 2}$ )

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Answer:

Solution:

$a = μ g = \frac{6}{10} [$ using $v = u + at]$ $\Rightarrow μ = \frac{6}{10 \times g} = \frac{6}{10 \times 10} = 0.06$

Stream:VITEEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: PYQ_2016

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