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PhysicsNLMSimple Application of NLMMedium2 minPYQ_2016

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A frictionless wire $AB$ is fixed on a sphere of radius $R$ . A very small spherical ball slips on this wire. The time taken by this ball to slip from A to $B$ is

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Solution:

Acceleration of body along $AB$ is g $cos θ$ Distance travelled in time $t$ sec $=$ $A B = \frac{1}{2} (g cos θ) t^{2}$ From $Δ ABC, AB = 2 R cos θ$ Thus, $2 R cos θ = \frac{1}{2} g cos θ t^{2}$ $\Rightarrow t^{2} = \frac{4 R}{g} \Rightarrow t = 2 \frac{R}{g}$

Stream:BITSATSubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: PYQ_2016

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